Difference between revisions of "1956 AHSME Problems/Problem 47"

(Created page with "In 1 day, <math>x</math> machines can do <math>\frac {1}{3}</math> of the job , and <math>x + 3</math> machines<math> \frac {1}{2}</math> of the job. So <math>3</math> machi...")
 
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Latest revision as of 08:42, 6 November 2017

In 1 day, $x$ machines can do $\frac {1}{3}$ of the job , and $x + 3$ machines$\frac {1}{2}$ of the job. So $3$ machines can do $\frac {1}{2} -\frac {1}{3}=\frac {1}{6}$ of the job in 1 day, and 1 machine can do$\frac {1}{18}$ of the job in 1 day. Hence, **18** days are needed for 1 machine to complete the job;