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Difference between revisions of "1956 AHSME Problems/Problem 9"

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== Solution ==
 
  
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Notice that the first part and the second part of the expression are the same things, just in a different order, ie 3 and the 6 are switched around.
 
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Therefore, the question is reduced to
 
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<cmath>2 \cdot [\root{3}{\root{6}{a^{9}}}]</cmath>
 
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Therefore, the answer is <math>\fbox{(A) 10}</math>
 

Revision as of 14:48, 31 August 2019

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