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1956 AHSME Problems/Problem 9

Revision as of 14:47, 31 August 2019 by Mr.peppa (talk | contribs) (Created page with "== Solution == Notice that the first part and the second part of the expression are the same things, just in a different order, ie 3 and the 6 are switched around. Therefore,...")
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Solution

Notice that the first part and the second part of the expression are the same things, just in a different order, ie 3 and the 6 are switched around. Therefore, the question is reduced to \[2 \cdot [root{3}{root{6}{a^{9}}}]\]

Therefore, the answer is $\fbox{(A) 10}$

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