Difference between revisions of "1959 AHSME Problems/Problem 10"
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Latest revision as of 00:39, 1 June 2020
In with , a point is taken on at a distance from . Point is joined to in the prolongation of so that is equal in area to . Then is:
Solution
Note that . Since , we have , so that . Therefore, . Thusly, our answer is , and we are done.