Difference between revisions of "1959 AHSME Problems/Problem 5"
(Created page with "== Problem 5== The value of <math>\left(256\right)^{.16}\left(256\right)^{.09}</math> is: <math>\textbf{(A)}\ 4 \qquad \\ \textbf{(B)}\ 16\qquad \\ \textbf{(C)}\ 64\qquad \\ ...") |
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Revision as of 00:08, 6 July 2016
Problem 5
The value of is:
Solution
When we multiply numbers with exponents, we add tne exponents together and leave the bases unchanged. We can apply this concept to computate : Now we can convert the decimal exponent to a fraction: Now, let us convert the expression into radical form. Since is the denominator of the fractional exponent, it will be the index exponent: Since , we can solve for the fourth root of : Therefore,