Difference between revisions of "1961 AHSME Problems/Problem 10"

(Created page with 'Each side of triangle <math>ABC</math> is 12 units. <math>D</math> is the foot of the perpendicular dropped from <math>A</math> on <math>BC</math>, and <math>E</math> is the midp…')
 
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Each side of triangle <math>ABC</math> is 12 units. <math>D</math> is the foot of the perpendicular dropped from <math>A</math> on <math>BC</math>, and <math>E</math> is the midpoint of <math>AD</math>. The length of <math>BE</math>, in the same unit, is:
 
Each side of triangle <math>ABC</math> is 12 units. <math>D</math> is the foot of the perpendicular dropped from <math>A</math> on <math>BC</math>, and <math>E</math> is the midpoint of <math>AD</math>. The length of <math>BE</math>, in the same unit, is:
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Revision as of 12:36, 5 July 2013

Each side of triangle $ABC$ is 12 units. $D$ is the foot of the perpendicular dropped from $A$ on $BC$, and $E$ is the midpoint of $AD$. The length of $BE$, in the same unit, is: The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png