# Difference between revisions of "1961 AHSME Problems/Problem 8"

(Created page with 'Let the two base angles of a triangle be ''A'' and ''B'', with ''B'' larger than ''A''. The altitude to the base divides the vertex angle ''C'' into two parts, <math>C_1 and C_2<…') |
|||

Line 1: | Line 1: | ||

− | Let the two base angles of a triangle be ''A'' and ''B'', with ''B'' larger than ''A''. The altitude to the base divides the vertex angle ''C'' into two parts, <math>C_1 and C_2</math>, with <math>C_2</math> adjacent to side ''a''. Then: | + | Let the two base angles of a triangle be ''A'' and ''B'', with ''B'' larger than ''A''. The altitude to the base divides the vertex angle ''C'' into two parts, <math>C_1</math> and <math>C_2</math>, with <math>C_2</math> adjacent to side ''a''. Then: |

(A) <math>C_1+C_2=A+B</math> | (A) <math>C_1+C_2=A+B</math> |

## Revision as of 17:09, 1 October 2009

Let the two base angles of a triangle be *A* and *B*, with *B* larger than *A*. The altitude to the base divides the vertex angle *C* into two parts, and , with adjacent to side *a*. Then:

(A)

(B)

(C)

(D)

(E)