Difference between revisions of "1962 AHSME Problems/Problem 13"

(Created page with "==Problem== <math>R</math> varies directly as <math>S</math> and inverse as <math>T</math>. When <math>R = \frac{4}{3}</math> and <math>T = \frac {9}{14}</math>, <math>S = \frac3...")
(No difference)

Revision as of 22:36, 9 November 2013

Problem

$R$ varies directly as $S$ and inverse as $T$. When $R = \frac{4}{3}$ and $T = \frac {9}{14}$, $S = \frac37$. Find $S$ when $R = \sqrt {48}$ and $T = \sqrt {75}$.

Solution

"Unsolved"