Difference between revisions of "1963 TMTA High School Algebra I Contest Problem 38"
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The answer is <math>\boxed{\text{(A)}}</math>. | The answer is <math>\boxed{\text{(A)}}</math>. | ||
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| + | == See Also == | ||
| + | {{Succession box | ||
| + | |header=[[1963 TMTA High School Mathematics Contests]] ([[1963 TMTA High School Algebra I Contest Problems|Problems]]) | ||
| + | |before=[[1963 TMTA High School Algebra I Contest Problem 37| Problem 37]] | ||
| + | |title=[[TMTA High School Mathematics Contest Past Problems/Solutions]] | ||
| + | |after=[[1963 TMTA High School Algebra I Contest Problem 39|Problem 39]] | ||
| + | }} | ||
Latest revision as of 12:39, 2 February 2021
Problem
A farmer sold 
hogs for 
Some were sold for 
, and the remainder were sold for 
each. How many were sold at each?
Solution
If there were 
hogs sold at 
dollars each, then there were 
hogs sold at 
dollars each. Using this, we can construct an equation which lets us solve for , the number of hogs sold at dollars each.
![\[30h + 40(60-h) = 2030\]](http://latex.artofproblemsolving.com/7/4/0/7401788c15721ad9f3b51c8791134f8aafe6e09a.png)
![\[30h - 40h + 2400 = 2030\]](http://latex.artofproblemsolving.com/e/1/d/e1d569ddf42160962371e03ebcd16364d1c9c683.png)
![\[-10h = -370\]](http://latex.artofproblemsolving.com/f/a/3/fa3fa8be5ff091f39eec9f7a8561aab8e4148aa6.png)
![\[h = \frac{-370}{-10} = 37.\]](http://latex.artofproblemsolving.com/a/5/5/a55859292fd1a11d49025a3255abad23d43f67f0.png)
The answer is 
.
See Also
| 1963 TMTA High School Mathematics Contests (Problems) | ||
| Preceded by Problem 37 |
TMTA High School Mathematics Contest Past Problems/Solutions | Followed by Problem 39 |
