Difference between revisions of "1964 AHSME Problems/Problem 35"

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==Problem==
 
==Problem==
  
The sides of a triangle are of lengths <math>13</math>, <math>14</math>, and <math>15</math>. The altitudes of the triangle meet at point <math>H</math>. if <math>AD</math> is teh altitude to the side of length <math>14</math>, the ratio <math>HD:HA</math> is:
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The sides of a triangle are of lengths <math>13</math>, <math>14</math>, and <math>15</math>. The altitudes of the triangle meet at point <math>H</math>. if <math>AD</math> is the altitude to the side of length <math>14</math>, the ratio <math>HD:HA</math> is:
  
 
<math>\textbf{(A) }3:11\qquad\textbf{(B) }5:11\qquad\textbf{(C) }1:2\qquad\textbf{(D) }2:3\qquad \textbf{(E) }25:33</math>
 
<math>\textbf{(A) }3:11\qquad\textbf{(B) }5:11\qquad\textbf{(C) }1:2\qquad\textbf{(D) }2:3\qquad \textbf{(E) }25:33</math>

Revision as of 17:09, 5 March 2014

Problem

The sides of a triangle are of lengths $13$, $14$, and $15$. The altitudes of the triangle meet at point $H$. if $AD$ is the altitude to the side of length $14$, the ratio $HD:HA$ is:

$\textbf{(A) }3:11\qquad\textbf{(B) }5:11\qquad\textbf{(C) }1:2\qquad\textbf{(D) }2:3\qquad \textbf{(E) }25:33$

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