Difference between revisions of "1965 AHSME Problems/Problem 15"
(Created page with "We begin by converting both <math>25_b</math> and <math>52_b</math> to base <math>10</math>. <math>25_b = 2b+5</math> in base <math>10</math> and <math>52_b = 5b+2</math> base...") |
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Latest revision as of 11:12, 10 June 2016
We begin by converting both 
and 
to base 
. 
in base and 
base . The problem tells us that 
, yielding 
as our final answer.
