1965 AHSME Problems/Problem 15
Revision as of 11:12, 10 June 2016 by Dot22 (Created page with "We begin by converting both <math>25_b</math> and <math>52_b</math> to base <math>10</math>. <math>25_b = 2b+5</math> in base <math>10</math> and <math>52_b = 5b+2</math> base...")
We begin by converting both and to base . in base and base . The problem tells us that , yielding as our final answer.