# 1965 AHSME Problems/Problem 6

## Problem 6

If then equals:

## Solution

Notice that . Therefore, the condition we are looking for is , or .

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Revision as of 14:09, 29 January 2020 by Dividend (talk | contribs) (Created page with "== Problem 6== If <math>10^{\log_{10}9} = 8x + 5</math> then <math>x</math> equals: <math>\textbf{(A)}\ 0 \qquad \textbf{(B) }\ \frac {1}{2} \qquad \textbf{(C) }\ \frac {...")

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If then equals:

Notice that . Therefore, the condition we are looking for is , or .

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