Difference between revisions of "1969 AHSME Problems/Problem 17"

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== Solution ==
 
== Solution ==
<math>\fbox{d}</math>
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<math>\fbox{D}</math>
  
 
== See also ==
 
== See also ==

Revision as of 03:19, 1 October 2014

Problem

The equation $2^{2x}-8\cdot 2^x+12=0$ is satisfied by:

$\text{(A) } log(3)\quad \text{(B) } \tfrac{1}{2}log(6)\quad \text{(C) } 1+log(\tfrac{3}{2})\quad \text{(D) } 1+\frac{log(3)}{log(2)}\quad \text{(E) none of these}$

Solution

$\fbox{D}$

See also

1969 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 16
Followed by
Problem 18
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35
All AHSME Problems and Solutions

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