Difference between revisions of "1970 AMC 12 Problems/Problem 2"
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A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is | A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is | ||
| − | <math>\mathrm{(A)}\ \frac 2\pi\qquad \mathrm{(B)}\ \frac pi\2\qquad \mathrm{(C)}\ \frac 45\qquad \mathrm{(D)}\ \frac 56\qquad \mathrm{(E)}\ \frac 78</math> | + | <math>\mathrm{(A)}\ \frac 2\pi\qquad \mathrm{(B)}\ \frac \pi\2\qquad \mathrm{(C)}\ \frac 45\qquad \mathrm{(D)}\ \frac 56\qquad \mathrm{(E)}\ \frac 78</math> |
== Solution == | == Solution == | ||
Revision as of 12:36, 9 January 2008
Problem
A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is
$\mathrm{(A)}\ \frac 2\pi\qquad \mathrm{(B)}\ \frac \pi\2\qquad \mathrm{(C)}\ \frac 45\qquad \mathrm{(D)}\ \frac 56\qquad \mathrm{(E)}\ \frac 78$ (Error compiling LaTeX. Unknown error_msg)
