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1970 AMC 12 Problems/Problem 2

Revision as of 12:35, 9 January 2008 by CHONGWON (talk | contribs) (→‎Problem)

Problem

A square and a circle have equal perimeters. The ratio of the area of the circle to the area of the square is

$\mathrm{(A)}\ \frac 2\pi\qquad \mathrm{(B)}\ \frac 34\qquad \mathrm{(C)}\ \frac 45\qquad \mathrm{(D)}\ \frac 56\qquad \mathrm{(E)}\ \frac 78$

Solution

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