# Difference between revisions of "1972 AHSME Problems/Problem 25"

(Created page with "==Solution== We note that <math>25^2+60^2=65^2</math> and <math>39^2+52^2=65^2</math> so our answer is <math>\boxed{65}</math>. -Pleaseletmewin") |
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+ | Inscribed in a circle is a quadrilateral having sides of lengths <math>25,~39,~52</math>, and <math>60</math> taken consecutively. The diameter of this circle has length | ||

+ | |||

+ | <math>\textbf{(A) }62\qquad \textbf{(B) }63\qquad \textbf{(C) }65\qquad \textbf{(D) }66\qquad \textbf{(E) }69</math> | ||

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==Solution== | ==Solution== | ||

− | We note that <math>25^2+60^2=65^2</math> and <math>39^2+52^2=65^2</math> so our answer is <math>\boxed{ | + | We note that <math>25^2+60^2=65^2</math> and <math>39^2+52^2=65^2</math> so our answer is <math>\boxed{C}</math>. |

-Pleaseletmewin | -Pleaseletmewin |

## Revision as of 16:02, 2 August 2020

Inscribed in a circle is a quadrilateral having sides of lengths , and taken consecutively. The diameter of this circle has length

## Solution

We note that and so our answer is .

-Pleaseletmewin