Difference between revisions of "1972 IMO Problems/Problem 3"

(Created page with "Let m and n be arbitrary non-negative integers. Prove that ((2m)!(2n)!)/mn!(m+n)! is an integer. (0! = 1.)")
 
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Let m and n be arbitrary non-negative integers. Prove that
 
Let m and n be arbitrary non-negative integers. Prove that
  
  ((2m)!(2n)!)/mn!(m+n)!
+
<math>((2m)!(2n)!)/mn!(m+n)!</math>
  
 
is an integer. (0! = 1.)
 
is an integer. (0! = 1.)
 +
 +
== Solution ==

Revision as of 16:38, 17 October 2014

Let m and n be arbitrary non-negative integers. Prove that

$((2m)!(2n)!)/mn!(m+n)!$

is an integer. (0! = 1.)

Solution