Difference between revisions of "1973 AHSME Problems/Problem 23"
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| − | 2/ | + | There are three red faces, and two are on the card that is completely red, so our answer is <math>\frac{2}{3}</math> |
Revision as of 20:55, 21 February 2015
There are three red faces, and two are on the card that is completely red, so our answer is 
