1978 IMO Problems/Problem 1

Revision as of 16:15, 18 December 2018 by Hashtagmath (talk | contribs) (Created page with "==Problem== <math>m</math> and <math>n</math> are positive integers with <math>m < n</math>. The last three decimal digits of <math>1978^m</math> are the same as the last thre...")
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Problem

$m$ and $n$ are positive integers with $m < n$. The last three decimal digits of $1978^m$ are the same as the last three decimal digits of $1978^n$. Find $m$ and $n$ such that $m + n$ has the least possible value.

Solution

This problem needs a solution. If you have a solution for it, please help us out by adding it.