Difference between revisions of "1981 AHSME Problems/Problem 19"
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Latest revision as of 04:00, 9 July 2018
Problem 19
In , is the midpoint of side , bisects , and . If sides and have lengths and , respectively, then find .
Solution
Extend to meet at . Then , so and .
Since , (since is an angle bisector) and and share side , . Thus , and so , hence our answer is .