Difference between revisions of "1981 AHSME Problems/Problem 3"
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| − | The least common multiple of <math>\frac{1}{x}</math>, <math>\frac{1}{2x}</math>, and <math>\frac{1}{3x}</math> is <math>\frac{1}{6x}</math>. | + | The least common multiple of <math>\displaystyle{\frac{1}{x}}</math>, <math>\frac{1}{2x}</math>, and <math>\frac{1}{3x}</math> is <math>\frac{1}{6x}</math>. |
<math>\frac{1}{x}</math> = <math>\frac{6}{6x}</math>, <math>\frac{1}{2x}</math> = <math>\frac{3}{6x}</math>, <math>\frac{1}{3x}</math> = <math>\frac{2}{6x}</math>. | <math>\frac{1}{x}</math> = <math>\frac{6}{6x}</math>, <math>\frac{1}{2x}</math> = <math>\frac{3}{6x}</math>, <math>\frac{1}{3x}</math> = <math>\frac{2}{6x}</math>. | ||
Revision as of 16:08, 21 November 2018
Solution
The least common multiple of 
, 
, and 
is 
.
= 
, = 
, = 
.
+ + = 
The answer is (D) .
