Difference between revisions of "1982 AHSME Problems/Problem 12"
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Revision as of 16:44, 31 January 2019
Problem
Let , where and are constants. If , then equals
Solution
is an odd function shifted down 5 units. Thus, it can be written as where . Thus: and . Using this and the fact is odd, we can evaluate , which is:
Therefore, the answer is .