Difference between revisions of "1982 AHSME Problems/Problem 4"
Mathhayden (talk | contribs) (Created page with "by mathhayden (bad) perimeter=2r+pi2r=2r(pi+1) area=[pi(r^2)]/2 make them equal & solve for r: pi(r^2)/2=2r(pi+1) pi(r^2)=4r(pi+1) (r^2)=4r[(pi+1)/pi] r=4(pi+1)/pi =<math>...") |
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Revision as of 02:03, 7 April 2020
by mathhayden (bad)
perimeter=2r+pi2r=2r(pi+1)
area=[pi(r^2)]/2
make them equal & solve for r: pi(r^2)/2=2r(pi+1) pi(r^2)=4r(pi+1) (r^2)=4r[(pi+1)/pi] r=4(pi+1)/pi
=Ans.
Ans.
