Difference between revisions of "1984 AJHSME Problem 9"

Latest revision as of 21:59, 3 May 2023

This article has been proposed for deletion. The reason given is: AJHSME did not exist in 1984. Sysops: Before deleting this article, please check the article discussion pages and history.

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-== Problem ==
+{{delete | AJHSME did not exist in 1984}}
-The product of the 9 factors <math>\Big(1 - \frac12\Big)\Big(1 - \frac13\Big)\Big(1 - \frac14\Big)\cdots\Big(1 - \frac {1}{10}\Big) =</math>
-<math>\text{(A)}\ \frac {1}{10} \qquad \text{(B)}\ \frac {1}{9} \qquad \text{(C)}\ \frac {1}{2} \qquad \text{(D)}\ \frac {10}{11} \qquad \text{(E)}\ \frac {11}{2}</math>
-== Solution ==
-This product simplifies to:
-<cmath>\frac{1}{2} \cdot \frac{2}{3} \dots \frac{9}{10}.</cmath>
-Numerators and denominators cancel to yield the answer: <math>\boxed{\text{(A)} \frac{1}{10}}.</math>