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Difference between revisions of "1985 AJHSME Problem 1"

(Created page with "==Problem== <math>\frac{3\times 5}{9\times 11}\times \frac{7\times 9\times 11}{3\times 5\times 7}=</math> <cmath>\text{(A)}\ 1 \qquad \text{(B)}\ 0 \qquad \text{(C)}\ 49 \qq...")
(No difference)

Revision as of 18:20, 31 January 2021

Problem

$\frac{3\times 5}{9\times 11}\times \frac{7\times 9\times 11}{3\times 5\times 7}=$

\[\text{(A)}\ 1 \qquad \text{(B)}\ 0 \qquad \text{(C)}\ 49 \qquad \text{(D)} \frac{1}{49}\ \qquad \text{(E)}\ 50\]

Solution

$\frac{3\times 5}{9\times 11}\times \frac{7\times 9\times 11}{3\times 5\times 7}= \frac{3 \times 5 \times 7 \times 9 \times 11}{9 \times 11 \times 3 \times 5 \times 7} = \boxed{1}$

The answer is $\text{(A) 1}.$

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