Difference between revisions of "1986 AJHSME Problems/Problem 3"

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==Problem==
 
==Problem==
  
The smallest sum one could get by adding three different numbers from the set <math>\{ 7,25,-1,12,-3 \}</math> is
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The smallest [[sum]] one could get by adding three different numbers from the [[set]] <math>\{ 7,25,-1,12,-3 \}</math> is
  
 
<math>\text{(A)}\ -3 \qquad \text{(B)}\ -1 \qquad \text{(C)}\ 3 \qquad \text{(D)}\ 5 \qquad \text{(E)}\ 21</math>
 
<math>\text{(A)}\ -3 \qquad \text{(B)}\ -1 \qquad \text{(C)}\ 3 \qquad \text{(D)}\ 5 \qquad \text{(E)}\ 21</math>
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==See Also==
 
==See Also==
  
[[1986 AJHSME Problems]]
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{{AJHSME box|year=1986|num-b=2|num-a=4}}
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[[Category:Introductory Algebra Problems]]

Revision as of 17:46, 19 May 2009

Problem

The smallest sum one could get by adding three different numbers from the set $\{ 7,25,-1,12,-3 \}$ is

$\text{(A)}\ -3 \qquad \text{(B)}\ -1 \qquad \text{(C)}\ 3 \qquad \text{(D)}\ 5 \qquad \text{(E)}\ 21$

Solution

To find the smallest sum, we just have to find the smallest 3 numbers and add them together.

Obviously, the numbers are $-3, -1, 7$, and adding them gets us $3$.

$\boxed{\text{C}}$

See Also

1986 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions
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