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1986 AJHSME Problems/Problem 6

Revision as of 23:24, 23 January 2009 by Waffle (talk | contribs)

Problem

$\frac{2}{1-\frac{2}{3}}=$

$\text{(A)}\ -3 \qquad \text{(B)}\ -\frac{4}{3} \qquad \text{(C)}\ \frac{2}{3} \qquad \text{(D)}\ 2 \qquad \text{(E)}\ 6$

Solution

A rather simple problem, if you have a basic understanding of fractions.

Just simplify the bottom, getting us $\frac{2}{\frac{1}{3}}$, with which we multiply both sides by 3, getting us $\frac{6}{1}$, or $6$

See Also

1986 AJHSME Problems

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