1986 AJHSME Problems/Problem 6

Problem

$\frac{2}{1-\frac{2}{3}}=$

$\text{(A)}\ -3 \qquad \text{(B)}\ -\frac{4}{3} \qquad \text{(C)}\ \frac{2}{3} \qquad \text{(D)}\ 2 \qquad \text{(E)}\ 6$

Solution

Just simplify the bottom as $\frac{3}{3}-\frac{2}{3}=\frac{1}{3}$ , getting us $\frac{2}{\frac{1}{3}}$ , with which we multiply top and bottom by 3, we get $\frac{6}{1}$ , or $6$

$\boxed{\text{E}}$

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1986 AJHSME Problems/Problem 6

Problem

Solution

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