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1987 AJHSME Problems/Problem 10

Revision as of 14:01, 15 February 2009 by 5849206328x (talk | contribs) (New page: ==Problem== <math>4(299)+3(299)+2(299)+298=</math> <math>\text{(A)}\ 2889 \qquad \text{(B)}\ 2989 \qquad \text{(C)}\ 2991 \qquad \text{(D)}\ 2999 \qquad \text{(E)}\ 3009</math> ==Soluti...)
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Problem

$4(299)+3(299)+2(299)+298=$

$\text{(A)}\ 2889 \qquad \text{(B)}\ 2989 \qquad \text{(C)}\ 2991 \qquad \text{(D)}\ 2999 \qquad \text{(E)}\ 3009$

Solution

We can make use of the distributive property as follows: \begin{align*} 4(299)+3(299)+2(299)+298 &= 4(299)+3(299)+2(299)+1(299)-1 \\ &= (4+3+2+1)(299)-1 \\ &= 10(299)-1 \\ &= 2989 \\ \end{align*}

$\boxed{\text{B}}$

See Also

1987 AJHSME Problems

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