1987 IMO Problems/Problem 1

Revision as of 21:51, 24 November 2006 by Boy Soprano II (talk | contribs) (Resources)


Let $\displaystyle p_n (k)$ be the number of permutations of the set $\displaystyle \{ 1, \ldots , n \} , \; n \ge 1$, which have exactly $\displaystyle k$ fixed points. Prove that

$\sum_{k=0}^{n} k \cdot p_n (k) = n!$.

(Remark: A permutation $\displaystyle f$ of a set $\displaystyle S$ is a one-to-one mapping of $\displaystyle S$ onto itself. An element $\displaystyle i$ in $\displaystyle S$ is called a fixed point of the permutation $\displaystyle f$ if $\displaystyle f(i) = i$.)


The sum in questions simply counts the total number of fixed points in all permutations of the set. But for any element $\displaystyle i$ of the set, there are $\displaystyle (n-1)!$ permutations which have $\displaystyle i$ as a fixed point. Therefore

$\sum_{k=0}^{n} k \cdot p_n (k) = n!$,

as desired.

Alternate solutions are always welcome. If you have a different, elegant solution to this problem, please add it to this page.


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