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Difference between revisions of "1988 AJHSME Problems/Problem 3"

(New page: ==Problem== <math>\frac{1}{10}+\frac{2}{20}+\frac{3}{30} = </math> <math>\text{(A)}\ .1 \qquad \text{(B)}\ .123 \qquad \text{(C)}\ .2 \qquad \text{(D)}\ .3 \qquad \text{(E)}\ .6</math> ...)
(No difference)

Revision as of 06:53, 14 April 2009

Problem

$\frac{1}{10}+\frac{2}{20}+\frac{3}{30} =$

$\text{(A)}\ .1 \qquad \text{(B)}\ .123 \qquad \text{(C)}\ .2 \qquad \text{(D)}\ .3 \qquad \text{(E)}\ .6$

Solution

Each of the fractions simplifies to $\frac{1}{10}$, so this sum is \begin{align*} \frac{1}{10}+\frac{1}{10}+\frac{1}{10} &= \frac{3}{10} \\ &= .3 \rightarrow \boxed{\text{D}} \end{align*}

See Also

1988 AJHSME Problems

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