Difference between revisions of "1989 AHSME Problems/Problem 3"
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Let <math>x</math> be the width of a rectangle so that the side of the square is <math>3x</math>. Since <math>2(3x)+2(x)=24</math> we have <math>x=3</math>. Thus the area of the square is <math>(3\cdot3)^2=81</math>. | Let <math>x</math> be the width of a rectangle so that the side of the square is <math>3x</math>. Since <math>2(3x)+2(x)=24</math> we have <math>x=3</math>. Thus the area of the square is <math>(3\cdot3)^2=81</math>. | ||
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Revision as of 13:47, 5 July 2013
Let 
be the width of a rectangle so that the side of the square is 
. Since 
we have 
. Thus the area of the square is 
.
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