# Difference between revisions of "1990 AHSME Problems/Problem 1"

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Cross-multiplying leaves | Cross-multiplying leaves | ||

− | <math><cmath> \begin{align*}\dfrac{x^2}{8} &= 8\\ x^2 &= 64\\ \sqrt{x} &= \sqrt{64}\\ x &= \pm 8\end{align*} </cmath></math> | + | <math><cmath> \begin{align*}\dfrac{x^2}{8} &= 8\\ x^2 &= 64\\ \sqrt{x^2} &= \sqrt{64}\\ x &= \pm 8\end{align*} </cmath></math> |

So the answer is <math>\boxed{\text{(E)} \, \pm 8}</math>. | So the answer is <math>\boxed{\text{(E)} \, \pm 8}</math>. | ||

{{MAA Notice}} | {{MAA Notice}} |

## Revision as of 04:03, 4 November 2013

## Problem

If , then

## Solution

Cross-multiplying leaves

$<cmath> \begin{align*}\dfrac{x^2}{8} &= 8\\ x^2 &= 64\\ \sqrt{x^2} &= \sqrt{64}\\ x &= \pm 8\end{align*} </cmath>$ (Error compiling LaTeX. ! Package amsmath Error: \begin{align*} allowed only in paragraph mode.)

So the answer is . The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.