Difference between revisions of "1990 AHSME Problems/Problem 12"
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== Solution == | == Solution == | ||
− | <math>\fbox{D}</math> | + | If <math>f(u)=-\sqrt2</math>, then <math>au^2=0\implies u=0</math>. Therefore <math>f(\sqrt2)=0\implies 2a=\sqrt2</math>, so <math>\fbox{D}</math> |
== See also == | == See also == |
Revision as of 04:32, 4 February 2016
Problem
Let be the function defined by for some positive . If then
Solution
If , then . Therefore , so
See also
1990 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 11 |
Followed by Problem 13 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
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