1990 AJHSME Problems/Problem 10

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Solution

Looking at the positions of the letters, we see that if the date behind $\text{Q}$ is $q$, then the date behind $\textbf{A}$ is $q-6$ and the date behind $\textbf{B}$ is $q+6$. Thus, their sum is $2q$.

The date behind $\text{C}$ is $q-7$, so the desired letter is the one for which the date behind it is $2q-(q-7)=q+7$. This is letter $\text{P}\rightarrow \boxed{\text{A}}$.

See Also

1990 AJHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
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All AJHSME/AMC 8 Problems and Solutions

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