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Difference between revisions of "1993 AJHSME Problems/Problem 1"

(Created page with '==Problem== Which pair of numbers does NOT have a product equal to <math>36</math>? <math> \text{(A)}\ \{-4,-9\}\qquad\text{(B)}\ \{-3,-12\}\qquad\text{(C)}\ \left\{\frac{1}{2},-…')
 
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Since C is the only ordered pair which doesn't equal 36, <math>\boxed{C}</math> is the answer.
 
Since C is the only ordered pair which doesn't equal 36, <math>\boxed{C}</math> is the answer.
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==See Also==
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{{AJHSME Box|year=1993|before=First<br />Question|num-a=2}}

Revision as of 21:56, 9 June 2011

Problem

Which pair of numbers does NOT have a product equal to $36$? $\text{(A)}\ \{-4,-9\}\qquad\text{(B)}\ \{-3,-12\}\qquad\text{(C)}\ \left\{\frac{1}{2},-72\right\}\qquad\text{(D)}\ \{ 1,36\}\qquad\text{(E)}\ \left\{\frac{3}{2},24\right\}$

Solution

A.The ordered pair ${-4,-9}$ has a product of $-4*-9=36$

B. The ordered pair ${-3,-12}$ has a product of $-3*-12=36$

C. The ordered pair ${1/12, -72}$ has a product of $-36$

D. The ordered pair ${1, 36}$ has a product of $1*36=36$

E. The ordered pair ${3/2, 24}$ has a product of $3/2*24=36$

Since C is the only ordered pair which doesn't equal 36, $\boxed{C}$ is the answer.

See Also

Template:AJHSME Box

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