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Difference between revisions of "1994 AHSME Problems/Problem 19"

(Created page with "==Problem== Label one disk "<math>1</math>", two disks "<math>2</math>", three disks "<math>3</math>"<math>, ...,</math> fifty disks "<math>50</math>". Put these <math>1+2+3+ \cd...")
(No difference)

Revision as of 22:07, 27 June 2014

Problem

Label one disk "$1$", two disks "$2$", three disks "$3$"$, ...,$ fifty disks "$50$". Put these $1+2+3+ \cdots+50=1275$ labeled disks in a box. Disks are then drawn from the box at random without replacement. The minimum number of disks that must be drawn to guarantee drawing at least ten disks with the same label is

$\textbf{(A)}\ 10 \qquad\textbf{(B)}\ 51 \qquad\textbf{(C)}\ 415 \qquad\textbf{(D)}\ 451 \qquad\textbf{(E)}\ 501$

Solution

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