# Difference between revisions of "1998 PMWC Problems/Problem I1"

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If you factor the bottom, you get <math>(1*3*5)(1^{3}+2^{3}+3^{3}+4^{3}+5^{3})</math> | If you factor the bottom, you get <math>(1*3*5)(1^{3}+2^{3}+3^{3}+4^{3}+5^{3})</math> | ||

− | Dividing out the common factor, you get <math>\frac {1*2*3}{1*3*5}=\frac {6}{15}= \frac {2}{5}</math> | + | Dividing out the common factor, you get <math>\frac {1*2*3}{1*3*5}=\frac {6}{15}= \frac {2}{5}</math> |

## Latest revision as of 16:37, 8 August 2009

## Problem I1

Calculate:

## Solution

If you factor the top, you get

If you factor the bottom, you get

Dividing out the common factor, you get