Difference between revisions of "1999 AIME Problems/Problem 11"
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== Problem == | == Problem == | ||
| + | Given that <math>\displaystyle \sum_{k=1}^{35}\sin 5k=\tan \frac mn,</math> where angles are measured in degrees, and <math>\displaystyle m_{}</math> and <math>\displaystyle n_{}</math> are relatively prime positive integers that satisfy <math>\displaystyle \frac mn<90,</math> find <math>\displaystyle m+n.</math> | ||
== Solution == | == Solution == | ||
== See also == | == See also == | ||
| + | * [[1999_AIME_Problems/Problem_10|Previous Problem]] | ||
| + | * [[1999_AIME_Problems/Problem_12|Next Problem]] | ||
* [[1999 AIME Problems]] | * [[1999 AIME Problems]] | ||
Revision as of 02:02, 22 January 2007
Problem
Given that 
where angles are measured in degrees, and 
and 
are relatively prime positive integers that satisfy 
find 
