# Difference between revisions of "2000 AMC 10 Problems/Problem 11"

(New page: Two prime numbers between <math>4</math> and <math>18</math> are both odd. odd*odd=odd. odd-odd-odd=odd. Thus, we can discard the even choices. <math>ab-a-b=(a-1)(b-1)-1</math>. <mat...) |
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− | + | #REDIRECT [[2000 AMC 12 Problems/Problem 6]] | |

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## Latest revision as of 23:42, 26 November 2011

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