# Difference between revisions of "2000 AMC 10 Problems/Problem 8"

(New page: Let <math>f</math> be the number of freshman and s be the number of sophomores. <math>\frac{2}{5}f=\frac{4}{5}s</math>. <math>f=2s</math>. There are twice as many freshman as sophomores.) |
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There are twice as many freshman as sophomores. | There are twice as many freshman as sophomores. | ||

+ | D. |

## Revision as of 15:02, 7 January 2009

Let be the number of freshman and s be the number of sophomores.

. .

There are twice as many freshman as sophomores. D.