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Difference between revisions of "2000 AMC 10 Problems/Problem 9"
m
Line 1: Line 1:
 +
==Problem==
 +
 +
==Solution==
 +
 
<math>|x-2|=p</math>
 
<math>|x-2|=p</math>
 +
 
<math>x<2</math>, so <math>2-x=p</math>.
 
<math>x<2</math>, so <math>2-x=p</math>.
  
 
<math>x+p=2</math>.
 
<math>x+p=2</math>.
 +
 
<math>x-p=2-2p</math>.
 
<math>x-p=2-2p</math>.
  
−
C.
+
<math>\boxed{\text{C}}</math>

Revision as of 19:36, 8 January 2009

Problem

Solution

$|x-2|=p$

$x<2$, so $2-x=p$.

$x+p=2$.

$x-p=2-2p$.

$\boxed{\text{C}}$

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