2000 AMC 8 Problems/Problem 1

Revision as of 13:32, 18 March 2011 by Pidigits125 (talk | contribs) (See Also)

Problem

Aunt Anna is $42$ years old. Caitlin is $5$ years younger than Brianna, and Brianna is half as old as Aunt Anna. How old is Caitlin?

$\mathrm{(A)}\ 15 \qquad \mathrm{(B)}\ 16 \qquad \mathrm{(C)}\ 17 \qquad \mathrm{(D)}\ 21 \qquad \mathrm{(E)}\ 37$

Solution

If Brianna is half as old as Aunt Anna, then Briana is $42/2$ years old, or $21$ years old.

If Caitlin is $5$ years younger than Briana, she is $21-5$ years old, or $16$.

So, the answer is $\boxed{B}$

See Also

Next Problem 2000 AMC 8 Problems