2001 IMO Shortlist Problems/N6

Revision as of 09:12, 6 October 2008 by 1=2 (talk | contribs) (This should have been combinatorics, and how did it get to the shortlist anyways???)

Problem

Is it possible to find 100 positive integers not exceeding 25,000, such that all pairwise sums of them are different?

Solution

The biggest pairwise sum is $24999+25000=49999$, and there are $\binom{100}{2}=50050$ sums. Thus by the Pigeonhole Principle, there must be at least two sums which are equal.

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