Difference between revisions of "2002 AMC 12A Problems/Problem 3"
(New page: ==Problem== According to the standard convention for exponentiation, <cmath> 2^{2^{2^{2}}} = 2^{(2^{(2^2)})} = 2^{16} = 65536. </cmath> If the order in which the exponentiations are perf...) |
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Revision as of 18:26, 6 October 2008
Problem
According to the standard convention for exponentiation,
![\[2^{2^{2^{2}}} = 2^{(2^{(2^2)})} = 2^{16} = 65536.\]](http://latex.artofproblemsolving.com/2/9/d/29dee8eac6c7812722f0013ad002044b30d8f220.png)
If the order in which the exponentiations are performed is changed, how many other values are possible?
