Difference between revisions of "2002 AMC 12P Problems/Problem 14"

(Solution)
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== Solution ==
 
== Solution ==
This problem is literally almost an exact copy of [[2009 AMC 12A Problems/Problem 15|Solution]], or arguably easier.
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This problem is literally almost an exact copy of [[2009 AMC 12A Problems/Problem 15|2009 AMC 12A Problem 15]], or arguably easier.
  
 
== See also ==
 
== See also ==
 
{{AMC12 box|year=2002|ab=P|num-b=13|num-a=15}}
 
{{AMC12 box|year=2002|ab=P|num-b=13|num-a=15}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 02:51, 31 December 2023

Problem

Find $i + 2i^2 +3i^3 + ... + 2002i^{2002}.$

$\text{(A) }-999 + 1002i \qquad \text{(B) }-1002 + 999i \qquad \text{(C) }-1001 + 1000i \qquad \text{(D) }-1002 + 1001i \qquad \text{(E) }i$

Solution

This problem is literally almost an exact copy of 2009 AMC 12A Problem 15, or arguably easier.

See also

2002 AMC 12P (ProblemsAnswer KeyResources)
Preceded by
Problem 13
Followed by
Problem 15
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions

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