Difference between revisions of "2002 AMC 12P Problems/Problem 22"
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== Solution == | == Solution == | ||
| + | <math>\boxed {\text{(D) }188.5}</math> | ||
== See also == | == See also == | ||
{{AMC12 box|year=2002|ab=P|num-b=21|num-a=23}} | {{AMC12 box|year=2002|ab=P|num-b=21|num-a=23}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Latest revision as of 22:15, 10 March 2024
Problem
Under the new AMC 
scoring method, 
points are given for each correct answer, 
points are given for each unanswered question, and no points are given for an incorrect answer. Some of the possible scores between 
and 
can be obtained in only one way, for example, a score of 
can be obtained with 
correct answers, 
unanswered question, and 
incorrect answers, and also with 
correct answers and 
unanswered questions. There are scores that can be obtained in exactly three ways. What is their sum?
Solution
See also
| 2002 AMC 12P (Problems • Answer Key • Resources) | |
| Preceded by Problem 21 |
Followed by Problem 23 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
