Difference between revisions of "2002 AMC 12P Problems/Problem 7"
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== Problem == | == Problem == | ||
| − | How many three-digit numbers have at least one <math>2</math> and at least one <math>3</math> | + | How many three-digit numbers have at least one <math>2</math> and at least one <math>3?</math> |
<math> | <math> | ||
Revision as of 00:45, 30 December 2023
Problem
How many three-digit numbers have at least one 
and at least one 
Solution
If 
, then 
. Since 
, 
must be 
to some factor of 6. Thus, there are four (3, 9, 27, 729) possible values of 
.
See also
| 2002 AMC 12P (Problems • Answer Key • Resources) | |
| Preceded by Problem 6 |
Followed by Problem 8 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
