Difference between revisions of "2002 AMC 8 Problems/Problem 14"
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Next, we take off the extra <math>20\%</math> as asked by the problem. <math>70\cdot0.80=56</math> | Next, we take off the extra <math>20\%</math> as asked by the problem. <math>70\cdot0.80=56</math> | ||
− | So the final price of an item is | + | So the final price of an item is \$56. We have to do <math>100-56</math> because <math>56</math> was the final price and we wanted the discount. |
<math>100-56=44</math> so the final discount was <math>\boxed{\text{(B)}\ 44\%}</math>. | <math>100-56=44</math> so the final discount was <math>\boxed{\text{(B)}\ 44\%}</math>. | ||
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===Solution 2=== | ===Solution 2=== | ||
− | Assume the price was | + | Assume the price was \$100. We can just do <math>100\cdot0.7\cdot0.8=56</math> and then do <math>100-56=\boxed{\text{(B)}\ 44}</math>. That is the discount percentage wise. |
==See Also== | ==See Also== | ||
{{AMC8 box|year=2002|num-b=13|num-a=15}} | {{AMC8 box|year=2002|num-b=13|num-a=15}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 09:17, 2 April 2020
Problem
A merchant offers a large group of items at off. Later, the merchant takes off these sale prices and claims that the final price of these items is off the original price. The total discount is
Solution
Solution 1
Let's assume that each item is dollars. First we take off off of dollars.
Next, we take off the extra as asked by the problem.
So the final price of an item is $56. We have to do because was the final price and we wanted the discount.
so the final discount was .
Solution 2
Assume the price was $100. We can just do and then do . That is the discount percentage wise.
See Also
2002 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 13 |
Followed by Problem 15 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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